Which of the following postulate of Bohr's model of hydrogen atom in not in agreement with quantum mechanical model of an atom ?
Show Hint
- An atom in a stationary state does not emit electromagnetic radiation as long as it stays in the same state
- An atom can take only certain distinct energies \( E_1 \), \( E_2 \), \( E_3 \), etc. These allowed states of constant energy are called the stationary states of atom
- When an electron makes a transition from a higher energy stationary state to a lower energy stationary state, then it emits a photon of light
- The electron in a H atom's stationary state moves in a circle around the nucleus
The Correct Option is D
Solution and Explanation
Top Questions on Atomic Structure
- What is the maximum wavelength to excite a hydrogen atom?
- KEAM - 2025
- Physics
- Atomic Structure
- In a hydrogen-like ion, the energy difference between the 2nd excitation energy state and ground is 108.8 eV. The atomic number of the ion is:
- JEE Main - 2025
- Physics
- Atomic Structure
- Consider the ground state of an atom (Z = 24). How many electrons are arranged with Azimuthal quantum number $ l = 1 $ and $ l = 2 $ respectively?
- JEE Main - 2025
- Chemistry
- Atomic Structure
- What is the molecular mass of \( \text{K}_2\text{SO}_4 \)?
- VITEEE - 2025
- Chemistry
- Atomic Structure
- What is the molecular mass of $ \text{Na}_2\text{SO}_4 $?
- MHT CET - 2025
- Chemistry
- Atomic Structure
Questions Asked in JEE Main exam
If $10 \sin^4 \theta + 15 \cos^4 \theta = 6$, then the value of $\frac{27 \csc^6 \theta + 8 \sec^6 \theta}{16 \sec^8 \theta}$ is:
- JEE Main - 2025
- Trigonometric Identities
If the area of the region $\{ (x, y) : |x - 5| \leq y \leq 4\sqrt{x} \}$ is $A$, then $3A$ is equal to
- JEE Main - 2025
- Area between Two Curves
Let $A = \begin{bmatrix} \cos \theta & 0 & -\sin \theta \\ 0 & 1 & 0 \\ \sin \theta & 0 & \cos \theta \end{bmatrix}$. If for some $\theta \in (0, \pi)$, $A^2 = A^T$, then the sum of the diagonal elements of the matrix $(A + I)^3 + (A - I)^3 - 6A$ is equal to
- JEE Main - 2025
- Matrices
Let $A = \{ z \in \mathbb{C} : |z - 2 - i| = 3 \}$, $B = \{ z \in \mathbb{C} : \text{Re}(z - iz) = 2 \}$, and $S = A \cap B$. Then $\sum_{z \in S} |z|^2$ is equal to
- JEE Main - 2025
- Determinants
Let $C$ be the circle $x^2 + (y - 1)^2 = 2$, $E_1$ and $E_2$ be two ellipses whose centres lie at the origin and major axes lie on the $x$-axis and $y$-axis respectively. Let the straight line $x + y = 3$ touch the curves $C$, $E_1$, and $E_2$ at $P(x_1, y_1)$, $Q(x_2, y_2)$, and $R(x_3, y_3)$ respectively. Given that $P$ is the mid-point of the line segment $QR$ and $PQ = \frac{2\sqrt{2}}{3}$, the value of $9(x_1 y_1 + x_2 y_2 + x_3 y_3)$ is equal to
- JEE Main - 2025
- Coordinate Geometry