In this question, we are determining which compound is least likely to produce effervescence of CO\(_2\) when reacted with aqueous NaHCO\(_3\). Effervescence occurs when an acid reacts with NaHCO\(_3\), producing CO\(_2\).
Compound (1) contains a hydroxyl group (-OH) and nitro groups (-NO\(_2\)) which will likely result in an acidic environment and cause effervescence with NaHCO\(_3\).
Compound (2) contains a carboxyl group (-COOH), a strong acid, which will react with NaHCO\(_3\) and release CO\(_2\).
Compound (3) contains an amine group (-NH\(_3\)), which is basic and does not typically react with NaHCO\(_3\) to produce CO\(_2\).
Compound (4) contains a nitro group (-NO\(_2\)) but lacks a strongly acidic functional group that would promote CO\(_2\) production.
Thus, it is the least likely to produce CO\(_2\) effervescence in the presence of NaHCO\(_3\).
Therefore, the compound least likely to give effervescence of CO\(_2\) is compound (4).
A dipeptide, “x”, on complete hydrolysis gives “y” and “z”; “y” on treatment with aqueous HNO$_2$, produces lactic acid. On the other hand, “z” on heating gives the following cyclic molecule.
Based on the information given, the dipeptide X is:
List-I (Amino Acid) | List-II (Nature of Amino Acid) |
---|---|
(A) Valine | (I) Basic amino acid |
(B) Glycine | (II) Neutral optically active amino acid |
(C) Lysine | (III) Acidic amino acid |
(D) Glutamic acid | (IV) Neutral optically inactive amino acid |
Match List-I with List-II.
Choose the correct answer from the options given below :