Which element is a strong reducing agent in +2 oxidation state and why?
The element that acts as a strong reducing agent in its +2 oxidation state is Zinc (Zn).
Zinc has a relatively low standard electrode potential:
\( E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, \text{V} \)
This negative value indicates that metallic zinc readily loses electrons to form \( \text{Zn}^{2+} \) ions:
\( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \)
The more negative the \( E^\circ \) value, the stronger the reducing power, as it reflects a higher tendency to donate electrons.
Thus, in the +2 oxidation state, zinc acts as a strong reducing agent and is capable of reducing other chemical species by donating electrons.
Acidified \(KMnO_4\) oxidizes sulphite to:
Convert Propanoic acid to Ethane
If vector \( \mathbf{a} = 3 \hat{i} + 2 \hat{j} - \hat{k} \) \text{ and } \( \mathbf{b} = \hat{i} - \hat{j} + \hat{k} \), then which of the following is correct?