Which element is a strong reducing agent in +2 oxidation state and why?
The element that acts as a strong reducing agent in its +2 oxidation state is Zinc (Zn).
Zinc has a relatively low standard electrode potential:
\( E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, \text{V} \)
This negative value indicates that metallic zinc readily loses electrons to form \( \text{Zn}^{2+} \) ions:
\( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \)
The more negative the \( E^\circ \) value, the stronger the reducing power, as it reflects a higher tendency to donate electrons.
Thus, in the +2 oxidation state, zinc acts as a strong reducing agent and is capable of reducing other chemical species by donating electrons.
Convert Propanoic acid to Ethane
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]