Which element is a strong reducing agent in +2 oxidation state and why?
The element that acts as a strong reducing agent in its +2 oxidation state is Zinc (Zn).
Zinc has a relatively low standard electrode potential:
\( E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, \text{V} \)
This negative value indicates that metallic zinc readily loses electrons to form \( \text{Zn}^{2+} \) ions:
\( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \)
The more negative the \( E^\circ \) value, the stronger the reducing power, as it reflects a higher tendency to donate electrons.
Thus, in the +2 oxidation state, zinc acts as a strong reducing agent and is capable of reducing other chemical species by donating electrons.
Complete and balance the following chemical equations: (a) \[ 2MnO_4^-(aq) + 10I^-(aq) + 16H^+(aq) \rightarrow \] (b) \[ Cr_2O_7^{2-}(aq) + 6Fe^{2+}(aq) + 14H^+(aq) \rightarrow \]
"___ how little changes in the environment can have big repercussions" Tishani Doshi in Journey to the End of the Earth gives an awakening call for man. Analyse the theme of the lesson in the light of the above statement.