Which element is a strong reducing agent in +2 oxidation state and why?
The element that acts as a strong reducing agent in its +2 oxidation state is Zinc (Zn).
Zinc has a relatively low standard electrode potential:
\( E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, \text{V} \)
This negative value indicates that metallic zinc readily loses electrons to form \( \text{Zn}^{2+} \) ions:
\( \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \)
The more negative the \( E^\circ \) value, the stronger the reducing power, as it reflects a higher tendency to donate electrons.
Thus, in the +2 oxidation state, zinc acts as a strong reducing agent and is capable of reducing other chemical species by donating electrons.
Acidified \(KMnO_4\) oxidizes sulphite to:
Convert Propanoic acid to Ethane

A ladder of fixed length \( h \) is to be placed along the wall such that it is free to move along the height of the wall.
Based upon the above information, answer the following questions:
(iii) (b) If the foot of the ladder, whose length is 5 m, is being pulled towards the wall such that the rate of decrease of distance \( y \) is \( 2 \, \text{m/s} \), then at what rate is the height on the wall \( x \) increasing when the foot of the ladder is 3 m away from the wall?