CuO is getting reduced and H$_2$ is getting oxidized.
H$_2$ is getting reduced and CuO is getting oxidized.
CuO is the reducing agent.
H$_2$ is the reducing agent.
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The Correct Option isD
Solution and Explanation
In the reaction:
CuO + H$_2$ → Cu + H$_2$O
- CuO is reduced to Cu (gain of electrons)
- H$_2$ is oxidized to H$_2$O (loss of electrons)
Since H$_2$ donates electrons, it reduces CuO and is therefore the reducing agent.