Question

Assertion (A): Cu\(^{2+}\) iodide is not known.
Reason (R): Cu\(^{2+}\) has strong tendency to oxidise I\(^{-}\) to iodine.

• A. Both A and R are true and R is the correct explanation of A
• B. Both A and R are true but R is not the correct explanation of A
• C. A is true but R is false
• D. A is false but R is true

Hint:

Cu\(^{2+}\) is too oxidising for I\(^{-}\); instead of forming CuI\(_2\), iodine gets liberated and CuI forms.

Answer 1

The Correct Option is A

Cu\(^{2+}\) is a strong oxidising agent. Iodide (I\(^{-}\)) is easily oxidised to I\(_2\). Therefore, when we attempt to make CuI\(_2\), the following redox reaction occurs: \[ 2\text{Cu}^{2+} + 4\text{I}^{-} \rightarrow 2\text{CuI} + \text{I}_2 \] Thus, Cu\(^{2+}\) is reduced to Cu\(^+\), and I\(^{-}\) is oxidised to I\(_2\). Hence, CuI\(_2\) is unstable and not known. \[ \boxed{\text{Both A and R are true and R explains A.}} \]