Which among the following compounds give yellow solid when reacted with NaOI/NaOH?
Choose the correct answer from the options given below:
When alcohols are reacted with NaOI/NaOH, a yellow solid is produced due to the formation of iodine complexes.
Upon examining the compounds:
- (A) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_5 \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid.
- (B) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_2 \text{OH} \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid.
- (C) \( \text{CH}_3 \text{C}_2 \text{H}_5 \) (an aldehyde) does not react with NaOI/NaOH to produce a yellow solid.
- (D) \( \text{CH}_3 \text{OH} \) does not react with NaOI/NaOH to form a yellow solid.
- (E) \( \text{CH}_3 \text{CH}_2 \text{H} \) does not react with NaOI/NaOH to form a yellow solid.
Thus, the correct answer is (2).
Identify the structure of the final product (D) in the following sequence of the reactions :
Total number of $ sp^2 $ hybridised carbon atoms in product D is _____.
Given below are two statements :
In the light of the above statements, choose the most appropriate answer from the options given below :
The number of optically active products obtained from the complete ozonolysis of the given compound is :
Match List-I with List-II
Choose the correct answer from the options given below :
Match List-I with List-II.
Choose the correct answer from the options given below :