Question:

Which among the following compounds give yellow solid when reacted with NaOI/NaOH?
Choose the correct answer from the options given below:

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The reaction of alcohols with NaOI/NaOH often leads to yellow solid formation due to iodine complexation.
Updated On: Apr 23, 2025
  • (B), (C) and (E) Only
  • (A) and (C) Only
  • (C) and (D) Only
  • (A), (C) and (D) Only
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The Correct Option is B

Solution and Explanation

When alcohols are reacted with NaOI/NaOH, a yellow solid is produced due to the formation of iodine complexes. 
Upon examining the compounds: 
- (A) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_5 \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid. 
- (B) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_2 \text{OH} \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid. 
- (C) \( \text{CH}_3 \text{C}_2 \text{H}_5 \) (an aldehyde) does not react with NaOI/NaOH to produce a yellow solid. 
- (D) \( \text{CH}_3 \text{OH} \) does not react with NaOI/NaOH to form a yellow solid. 
- (E) \( \text{CH}_3 \text{CH}_2 \text{H} \) does not react with NaOI/NaOH to form a yellow solid. 
Thus, the correct answer is (2).

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