Which among the following compounds give yellow solid when reacted with NaOI/NaOH?
Choose the correct answer from the options given below:
When alcohols are reacted with NaOI/NaOH, a yellow solid is produced due to the formation of iodine complexes.
Upon examining the compounds:
- (A) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_5 \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid.
- (B) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_2 \text{OH} \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid.
- (C) \( \text{CH}_3 \text{C}_2 \text{H}_5 \) (an aldehyde) does not react with NaOI/NaOH to produce a yellow solid.
- (D) \( \text{CH}_3 \text{OH} \) does not react with NaOI/NaOH to form a yellow solid.
- (E) \( \text{CH}_3 \text{CH}_2 \text{H} \) does not react with NaOI/NaOH to form a yellow solid.
Thus, the correct answer is (2).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
A hydrocarbon which does not belong to the same homologous series of carbon compounds is
Statement-1: \( \text{ClF}_3 \) has 3 possible structures.
Statement-2: \( \text{III} \) is the most stable structure due to least lone pair-bond pair (lp-bp) repulsion.
Which of the following options is correct?
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: