Which among the following compounds give yellow solid when reacted with NaOI/NaOH? 
Choose the correct answer from the options given below:
Which among the following compounds give yellow solid when reacted with NaOI/NaOH?
Choose the correct answer from the options given below:
Show Hint
- (B), (C) and (E) Only
- (A) and (C) Only
- (C) and (D) Only
- (A), (C) and (D) Only
The Correct Option is B
Approach Solution - 1
The given question asks which compounds produce a yellow solid when reacted with NaOI/NaOH. This reaction is characteristic of the Haloform reaction, which occurs with methyl ketones (compounds containing the structure CH3COR) and gives a yellow precipitate of iodoform (CHI3).
- Identify the Compounds:
- (A) CH3-CH(OH)-C2H5
- (B) CH3-CH2-CH2-OH
- (C) CH3COC2H5
- (D) CH3COOH
- (E) CH3CH2CHO
- Determine Which Compounds are Methyl Ketones:
- Compound (C): CH3COC2H5 is a methyl ketone and will react to form iodoform.
- Compound (A): Upon oxidation with NaOI, CH3-CH(OH)-C2H5 can yield a methyl ketone structure (acetone), thus forming iodoform.
- Other Compounds: Compounds (B), (D), and (E) do not have the methyl ketone structure necessary for the iodoform reaction under standard conditions. Compound (E) is an aldehyde and will not react to form iodoform.
- Conclusion: Based on the above analysis, the compounds (A) and (C) give a yellow solid (iodoform) when reacted with NaOI/NaOH.
The correct answer is (A) and (C) Only.
Approach Solution -2
When alcohols are reacted with NaOI/NaOH, a yellow solid is produced due to the formation of iodine complexes.
Upon examining the compounds:
- (A) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_5 \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid.
- (B) \( \text{CH}_3 \text{CH}_2 \text{C}_2 \text{H}_2 \text{OH} \) (an alcohol) reacts with NaOI/NaOH, producing a yellow solid.
- (C) \( \text{CH}_3 \text{C}_2 \text{H}_5 \) (an aldehyde) does not react with NaOI/NaOH to produce a yellow solid.
- (D) \( \text{CH}_3 \text{OH} \) does not react with NaOI/NaOH to form a yellow solid.
- (E) \( \text{CH}_3 \text{CH}_2 \text{H} \) does not react with NaOI/NaOH to form a yellow solid.
Thus, the correct answer is (2).
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