\(\frac{2}{9}F\)
\(\frac{16}{9}F\)
\(\frac{8}{9}F\)
\(F\)
Let the masses are m and distance between them is l, then
F=\(\frac{Gm^2}{I^2}\)
When \(\frac{1}{3^{rd}}\) mass is transferred to the other then masses will be \(\frac{4m}{3}\) and \(\frac{2m}{3}\).
So new force will be
F′=\(G\frac{4m}{3}\)\(\frac{G\frac{4m}{3}×\frac{2m}{3}}{I^2}\)
=\(\frac{8}{9}\)\(\frac{Gm^2}{I^2}\)
=\(\frac{8}{9}F\)
\(\therefore ,\) The correct option is (C): \(\frac{8}{9}F\)
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
Different types of forces that are found in nature can be broadly categorized into two types:
Contact Forces can further be divided into the following types:
Action-at-a-Distance Force is exerted without the objects being in contact. The various types of Action-at-a-Distance Force are as follows: