\(\frac{2}{9}F\)
\(\frac{16}{9}F\)
\(\frac{8}{9}F\)
\(F\)
Let the masses are m and distance between them is l, then
F=\(\frac{Gm^2}{I^2}\)
When \(\frac{1}{3^{rd}}\) mass is transferred to the other then masses will be \(\frac{4m}{3}\) and \(\frac{2m}{3}\).
So new force will be
F′=\(G\frac{4m}{3}\)\(\frac{G\frac{4m}{3}×\frac{2m}{3}}{I^2}\)
=\(\frac{8}{9}\)\(\frac{Gm^2}{I^2}\)
=\(\frac{8}{9}F\)
\(\therefore ,\) The correct option is (C): \(\frac{8}{9}F\)
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
Different types of forces that are found in nature can be broadly categorized into two types:
Contact Forces can further be divided into the following types:
Action-at-a-Distance Force is exerted without the objects being in contact. The various types of Action-at-a-Distance Force are as follows: