\(\frac{2}{9}F\)
\(\frac{16}{9}F\)
\(\frac{8}{9}F\)
\(F\)

Let the masses are m and distance between them is l, then
F=\(\frac{Gm^2}{I^2}\)
When \(\frac{1}{3^{rd}}\) mass is transferred to the other then masses will be \(\frac{4m}{3}\) and \(\frac{2m}{3}\).
So new force will be
F′=\(G\frac{4m}{3}\)\(\frac{G\frac{4m}{3}×\frac{2m}{3}}{I^2}\)
=\(\frac{8}{9}\)\(\frac{Gm^2}{I^2}\)
=\(\frac{8}{9}F\)
\(\therefore ,\) The correct option is (C): \(\frac{8}{9}F\)
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.
Different types of forces that are found in nature can be broadly categorized into two types:
Contact Forces can further be divided into the following types:
Action-at-a-Distance Force is exerted without the objects being in contact. The various types of Action-at-a-Distance Force are as follows: