Let the force \( F \) be the force acting on the balloon. The force equation for the initial condition (with mass \( m \)) is: \[ F - mg = ma \]
Step 2: Force When Mass \( x \) is ReleasedThe force when the mass \( x \) is released becomes: \[ F = ma + mg \]
Step 3: Force After Releasing Mass \( x \)After releasing mass \( x \), the equation becomes: \[ F - (m - x)g = (m - x) 3a \]
Step 4: Substitute the Value of \( F \)Substituting the value of \( F \) from the previous equation: \[ Ma + mg - mg + xg = 3ma - 3xa \]
Step 5: Solve for \( x \)Solving for \( x \): \[ x = \frac{2ma}{g + 3a} \]
Final Answer: \[ x = \frac{2ma}{g + 3a} \]A body of mass of \(4\;kg\) experiences two forces \(\vec{F_1}=5\hat i+8\hat j+7\hat k \) and \(\vec{F_2}=3\hat i-4\hat j-3\hat k\) then acceleration acting on the body \(R\)
If \[ \frac{dy}{dx} + 2y \sec^2 x = 2 \sec^2 x + 3 \tan x \cdot \sec^2 x \] and
and \( f(0) = \frac{5}{4} \), then the value of \[ 12 \left( y \left( \frac{\pi}{4} \right) - \frac{1}{e^2} \right) \] equals to: