Step 1: Force Equation for Initial Condition
Let the force \( F \) be the force acting on the balloon. The force equation for the initial condition (with mass \( m \)) is: \[ F - mg = ma \]
Step 2: Force When Mass \( x \) is Released
The force when the mass \( x \) is released becomes: \[ F = ma + mg \]
Step 3: Force After Releasing Mass \( x \)
After releasing mass \( x \), the equation becomes: \[ F - (m - x)g = (m - x) 3a \]
Step 4: Substitute the Value of \( F \)
Substituting the value of \( F \) from the previous equation: \[ Ma + mg - mg + xg = 3ma - 3xa \]
Step 5: Solve for \( x \)
Solving for \( x \): \[ x = \frac{2ma}{g + 3a} \]
Final Answer: \[ x = \frac{2ma}{g + 3a} \]
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
Let A be a 3 × 3 matrix such that \(\text{det}(A) = 5\). If \(\text{det}(3 \, \text{adj}(2A)) = 2^{\alpha \cdot 3^{\beta} \cdot 5^{\gamma}}\), then \( (\alpha + \beta + \gamma) \) is equal to: