Question:

A force $ 6 \hat{k} $ is applied for $ \frac{5}{3} $ seconds on a body of mass 2 kg. If the initial velocity of the body was $ 3\hat{i} + 4\hat{j} $, then find the final velocity of the body.

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When a force is applied on an object, use Newton's second law to calculate the acceleration, and then apply the equation of motion to find the final velocity.
Updated On: Apr 12, 2025
  • \( 3\hat{i} + \hat{j} + 5\hat{k} \)
  • \( 3\hat{i} + 4\hat{j} + 5\hat{k} \)
  • \( 3\hat{i} + 2\hat{j} - 3\hat{k} \)
  • \( 3\hat{i} + 4\hat{j} - 5\hat{k} \)
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The Correct Option is B

Solution and Explanation

Step 1: Use Newton’s Second Law of Motion.
The force \( \vec{F} \) acting on the body is related to the acceleration \( \vec{a} \) by Newton's second law: \[ \vec{F} = m \vec{a} \] Given that the force is \( 6 \hat{k} \, \text{N} \) and the mass \( m = 2 \, \text{kg} \), the acceleration \( \vec{a} \) is: \[ \vec{a} = \frac{\vec{F}}{m} = \frac{6 \hat{k}}{2} = 3 \hat{k} \, \text{m/s}^2 \]
Step 2: Use the equation of motion to find the final velocity.
The equation for final velocity \( \vec{v_f} \) is: \[ \vec{v_f} = \vec{v_i} + \vec{a} \times t \] where:
\( \vec{v_i} = 3 \hat{i} + 4 \hat{j} \) is the initial velocity,
\( \vec{a} = 3 \hat{k} \) is the acceleration,
\( t = \frac{5}{3} \) seconds is the time duration.
Substituting the values into the equation: \[ \vec{v_f} = (3 \hat{i} + 4 \hat{j}) + (3 \hat{k}) \times \frac{5}{3} \] \[ \vec{v_f} = 3 \hat{i} + 4 \hat{j} + 5 \hat{k} \]
Step 3: Conclusion.
The final velocity of the body is \( 3 \hat{i} + 4 \hat{j} + 5 \hat{k} \), which corresponds to option (2).
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