Step 1: Use Newton’s Second Law of Motion.
The force \( \vec{F} \) acting on the body is related to the acceleration \( \vec{a} \) by Newton's second law:
\[
\vec{F} = m \vec{a}
\]
Given that the force is \( 6 \hat{k} \, \text{N} \) and the mass \( m = 2 \, \text{kg} \), the acceleration \( \vec{a} \) is:
\[
\vec{a} = \frac{\vec{F}}{m} = \frac{6 \hat{k}}{2} = 3 \hat{k} \, \text{m/s}^2
\]
Step 2: Use the equation of motion to find the final velocity.
The equation for final velocity \( \vec{v_f} \) is:
\[
\vec{v_f} = \vec{v_i} + \vec{a} \times t
\]
where:
\( \vec{v_i} = 3 \hat{i} + 4 \hat{j} \) is the initial velocity,
\( \vec{a} = 3 \hat{k} \) is the acceleration,
\( t = \frac{5}{3} \) seconds is the time duration.
Substituting the values into the equation:
\[
\vec{v_f} = (3 \hat{i} + 4 \hat{j}) + (3 \hat{k}) \times \frac{5}{3}
\]
\[
\vec{v_f} = 3 \hat{i} + 4 \hat{j} + 5 \hat{k}
\]
Step 3: Conclusion.
The final velocity of the body is \( 3 \hat{i} + 4 \hat{j} + 5 \hat{k} \), which corresponds to option (2).