Two long parallel conductors \(S_1\) and \(S_2\) are separated by a distance \(10\) cm and carrying currents of \(4\) A and \(2\) A respectively. The conductors are placed along x-axis in X–Y plane. There is a point P located between the conductors (as shown in figure). A charge particle of \(3π\) coulomb is passing through the point P with velocity \(\overrightarrow v=(2\hat i+3\hat j)\) m/s; where \(\hat i\) and \(\hat j\) represents unit vector along x & y axis respectively. The force acting on the charge particle is \(4π×10^{−5}(−x\hat i+2\hat j)N\). The value of x is:
Field at P is
=\(\bigg(\frac{µ_0×i_1}{2πr_1}–\frac{µ_0i_2}{2πr_2}\bigg)\bigg(−\hat k\bigg)\)
=\(−\bigg(\frac{µ_04}{2π×0.04}−\frac{µ_0×2}{2π×0.06}\bigg)\hat k=–\frac{µ_0×200}{6π}\hat k\)
Therefore, the force
\(\overrightarrow F=\overrightarrow {qv} ×\overrightarrow B\)
= \(3π(2\hat i+3\hat j)×\bigg(−\bigg(\frac{µ_0×200}{6π}\bigg)\hat k\bigg)\)
=\(3π\bigg(\frac{200µ_0}{3π\hat j}−\frac{100µ_0}{π}\hat i)\)
= \(200µ_0\hat j–300µ_0\hat i\)
= \(4π×10^{−5}(2\hat j–3\hat i)\)
\(Hence,\) \(x = 3\)
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
Semiconductors are a crystalline solid materials, whose electrical conductivity lies between a conductor and an insulator. Semiconductors are mainly used in the manufacturing of electronic devices like capacitors, transistors, diodes, Integrated circuits, etc.