Question

The reverse saturation current (I0) of a silicon diode at 27°C is \( 10^{-6} \) A. What will be the approximate value of I0 at 67°C? (Assume \( I_0 \) doubles for every 10°C rise in temperature)

• A. \( 1.6 \times 10^{-6} \) A
• B. \( 1.6 \times 10^{-5} \) A
• C. \( 8.0 \times 10^{-6} \) A
• D. \( 4.0 \times 10^{-6} \) A

Hint:

For temperature-dependent current changes in diodes, use the rule that the saturation current doubles for every 10°C increase in temperature.

Answer 1

The Correct Option is B

Given:

• Initial temperature: \( 27^\circ C \)
• Final temperature: \( 67^\circ C \)
• Initial \( I_0 = 10^{-6}\ \text{A} \)
• \( I_0 \) doubles every \( 10^\circ C \) rise

Step-by-Step:

\[ \Delta T = 67^\circ C - 27^\circ C = 40^\circ C \] \[ \text{Doublings} = \frac{40}{10} = 4 \] \[ I_0' = I_0 \cdot 2^4 = 10^{-6} \cdot 16 = 1.6 \times 10^{-5}\ \text{A} \]

✅ Final Answer:

\[ \boxed{1.6 \times 10^{-5}\ \text{A}} \]