Question:
Two identical circular loops of metal wire are lying on a table
without touching each other. Loop A carries a current which
increases with time. In response, the loop B
Two identical circular loops of metal wire are lying on a table
without touching each other. Loop A carries a current which
increases with time. In response, the loop B
Updated On: Jun 14, 2022
- remains stationary
- is attracted by the loop A
- is repelled by the loop A
- rotates about its CM, with CM fixed
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The Correct Option is C
Solution and Explanation
For understanding, let us assume that the two loops are lying
in the plane of paper as shown. The current in loop 1 will
produce $\odot$ magnetic field in loop 2. Therefore, increase in
current in loop 1 will produce an induced current in loop 2
which produces $\otimes$ magnetic field passing through it i.e.
induced current in loop 2 will also be clockwise as shown in
the figure.
The loops will now repel each other as the currents at the
nearest and farthest points of the two loops flow in opposite
directions.
in the plane of paper as shown. The current in loop 1 will
produce $\odot$ magnetic field in loop 2. Therefore, increase in
current in loop 1 will produce an induced current in loop 2
which produces $\otimes$ magnetic field passing through it i.e.
induced current in loop 2 will also be clockwise as shown in
the figure.
The loops will now repel each other as the currents at the
nearest and farthest points of the two loops flow in opposite
directions.
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Concepts Used:
Faradays Laws of Induction
There are two laws, given by Faraday which explain the phenomena of electromagnetic induction:
Faraday's First Law:
Whenever a conductor is placed in a varying magnetic field, an emf is induced. If the conductor circuit is closed, a current is induced, known as the induced current.
Faraday's Second Law:
The Emf induced inside a coil is equal to the rate of change of associated magnetic flux.
This law can be mathematically written as:
∈\(-N {\triangle \phi \over \triangle t}\)
