Question:

The current following through an inductance coil of self inductance 6 mH at different time instants is as shown. The emf induced between t = 20s and t = 40s is nearly
current following through an inductance coil

Updated On: Apr 1, 2025
  • 2 × 10-2 V
  • 3 × 10-4 V
  • 4 × 10-3 V
  • 30 × 102 V
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The Correct Option is B

Solution and Explanation

The equations describe the induced electromotive force (emf) in a circuit:

e=LdIdt |e| = L \frac{dI}{dt}

The magnitude of the emf (e|e|) is given by the product of inductance (LL) and the rate of change of current (dIdt\frac{dI}{dt}).

e=6×103[I2I1t2t1] |e| = 6 \times 10^{-3} \left[ \frac{I_2 - I_1}{t_2 - t_1} \right]

Substituting the values, the emf is calculated using the discrete current change over time.

e=6×103[14020] |e| = 6 \times 10^{-3} \left[ \frac{1}{40 - 20} \right]

Plugging in the specific time interval (t1=20t_1 = 20, t2=40t_2 = 40) and assuming the current change (ΔI=1\Delta I = 1).

e=3×104 V e = 3 \times 10^{-4} \text{ V}

The final result for the induced emf is 3×1043 \times 10^{-4} volts.

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