Total number of nucleophiles from the following is: $NH_3$, $PhSH$, $(H_3C_2S)_2$, $H_2C=CH_2$, $OH^-$, $H_3O^+$, $(CH_3)_2CO$, $NCH_3$
Show Hint
- 6
- 5
- 4
- 7
The Correct Option is A
Solution and Explanation
A nucleophile is a species that donates an electron pair to form a chemical bond in a reaction. The given species that can act as nucleophiles are: 1. NH3 (Ammonia)
2. PhSH (Phenyl thiol)
3. \({(H}_3{C}_2{S})_2\) (Dimethyl disulfide)
4. \({OH}^-\) (Hydroxide ion)
5. \({H}_3{O}^+\) (Hydronium ion)
6. \({NCH}_3\) (Methylamine) Thus, there are 6 nucleophiles in total.
Top Questions on Analytical Chemistry
- In LC-MS (Liquid Chromatography-Mass Spectrometry) instrument, the interface is applied between:
- NIPER JEE - 2025
- Pharmaceutical Sciences
- Analytical Chemistry
- Which form of electrochemical measurement does NOT involve electrolysis?
- NIPER JEE - 2025
- Pharmaceutical Sciences
- Analytical Chemistry
Given below are two statements:
Statement I: In the oxalic acid vs KMnO$_4$ (in the presence of dil H$_2$SO$_4$) titration the solution needs to be heated initially to 60°C, but no heating is required in Ferrous ammonium sulphate (FAS) vs KMnO$_4$ titration (in the presence of dil H$_2$SO$_4$).
Statement II: In oxalic acid vs KMnO$_4$ titration, the initial formation of MnSO$_4$ takes place at high temperature, which then acts as catalyst for further reaction. In the case of FAS vs KMnO$_4$, heating oxidizes Fe$^{2+}$ into Fe$^{3+}$ by oxygen of air and error may be introduced in the experiment.
In the light of the above statements, choose the correct answer from the options given below:
- JEE Main - 2025
- Chemistry
- Analytical Chemistry
- Which pair of ions among the following can be separated by precipitation method?
- WBJEE - 2025
- Chemistry
- Analytical Chemistry
Kjeldahl's method cannot be used for the estimation of nitrogen in which compound?
(A) (B) (C) (D) NH2-CH2-COOH C6H5-NH2 C6H5-N=N-C6H5 O2N-C6H4-NO2 - WBJEE - 2025
- Chemistry
- Analytical Chemistry
Questions Asked in JEE Main exam
- CrCl\(_3\).xNH\(_3\) can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558°C. Assuming 100\% ionization of this complex and coordination number of Cr is 6, the complex will be:
- JEE Main - 2025
- Colligative Properties
- Suppose that the number of terms in an A.P. is \( 2k, k \in \mathbb{N} \). If the sum of all odd terms of the A.P. is 40, the sum of all even terms is 55, and the last term of the A.P. exceeds the first term by 27, then \( k \) is equal to:
- JEE Main - 2025
- Arithmetic Progression
- If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
- JEE Main - 2025
- Complex numbers
- Let \( [x] \) denote the greatest integer function, and let \( m \) and \( n \) respectively be the numbers of the points, where the function \( f(x) = [x] + |x - 2| \), \( -2<x<3 \), is not continuous and not differentiable. Then \( m + n \) is equal to:
- JEE Main - 2025
- Differential Equations
- Let \( f(x) = \frac{x - 5}{x^2 - 3x + 2} \). If the range of \( f(x) \) is \( (-\infty, \alpha) \cup (\beta, \infty) \), then \( \alpha^2 + \beta^2 \) equals to.
- JEE Main - 2025
- Functions