Given below are two statements:
Statement I: In the oxalic acid vs KMnO$_4$ (in the presence of dil H$_2$SO$_4$) titration the solution needs to be heated initially to 60°C, but no heating is required in Ferrous ammonium sulphate (FAS) vs KMnO$_4$ titration (in the presence of dil H$_2$SO$_4$).
Statement II: In oxalic acid vs KMnO$_4$ titration, the initial formation of MnSO$_4$ takes place at high temperature, which then acts as catalyst for further reaction. In the case of FAS vs KMnO$_4$, heating oxidizes Fe$^{2+}$ into Fe$^{3+}$ by oxygen of air and error may be introduced in the experiment.
In the light of the above statements, choose the correct answer from the options given below:
Statement I:
In the oxalic acid vs $ KMnO_4 $ titration (in the presence of dilute $ H_2SO_4 $), the solution needs to be heated initially to $ 60^\circ C $. However, no heating is required in the Ferrous Ammonium Sulphate (FAS) vs $ KMnO_4 $ titration under similar conditions.
This statement is true.
In the titration of oxalic acid with $ KMnO_4 $, heating to around $ 60^\circ C $ is required to initiate the reaction because it is relatively slow at room temperature.
In contrast, the reaction between $ KMnO_4 $ and FAS is fast even at room temperature, so no initial heating is necessary.
Statement II:
In oxalic acid vs $ KMnO_4 $ titration, the initial formation of $ Mn^{2+} $ takes place at high temperature, which then acts as a catalyst (autocatalyst) for the further reaction. In the case of FAS vs $ KMnO_4 $, heating may cause oxidation of $ Fe^{2+} $ to $ Fe^{3+} $ by atmospheric oxygen, introducing errors in the experiment.
This statement is also true.
In the oxalic acid titration, the $ Mn^{2+} $ ions formed during the reaction act as an autocatalyst, increasing the reaction rate after some time. Since the initial formation of $ Mn^{2+} $ is slow, heating is required to speed up the process.
In the FAS titration, heating may lead to aerial oxidation of $ Fe^{2+} $ to $ Fe^{3+} $, which can interfere with accurate titration results.
Conclusion:
Both Statement I and Statement II are true.
Final Answer:
The final answer is $ \ \text{Both Statement I and Statement II are true} $.
40 mL of a mixture of CH\(_3\)COOH and HCl (aqueous solution) is titrated against 0.1 M NaOH solution conductometrically. Which of the following statement is correct?
During estimation of Nitrogen by Dumas' method of compound X (0.42 g) :
mL of $ N_2 $ gas will be liberated at STP. (nearest integer) $\text{(Given molar mass in g mol}^{-1}\text{ : C : 12, H : 1, N : 14})$
If the mean and the variance of 6, 4, a, 8, b, 12, 10, 13 are 9 and 9.25 respectively, then \(a + b + ab\) is equal to:
Given three identical bags each containing 10 balls, whose colours are as follows:
| Bag I | 3 Red | 2 Blue | 5 Green |
| Bag II | 4 Red | 3 Blue | 3 Green |
| Bag III | 5 Red | 1 Blue | 4 Green |
A person chooses a bag at random and takes out a ball. If the ball is Red, the probability that it is from Bag I is $ p $ and if the ball is Green, the probability that it is from Bag III is $ q $, then the value of $ \frac{1}{p} + \frac{1}{q} $ is:
If \( \theta \in \left[ -\frac{7\pi}{6}, \frac{4\pi}{3} \right] \), then the number of solutions of \[ \sqrt{3} \csc^2 \theta - 2(\sqrt{3} - 1)\csc \theta - 4 = 0 \] is equal to ______.