Question:
The real value of ‘α’ for which $\frac{1 -isinα}{1+ 2isinα}$ is purely real is
The real value of ‘α’ for which $\frac{1 -isinα}{1+ 2isinα}$ is purely real is
Updated On: Apr 10, 2025
- $ (n+1) \frac{\pi}{2}, n ∈ N $
- $ (2n+1) \frac{\pi}{2}, n ∈ N $
- $n{\pi}, n ∈ N $
- $ (2n-1) \frac{\pi}{2}, n ∈ N $
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The Correct Option is C
Solution and Explanation
The correct answer is Option (C) : $n{\pi}, n ∈ N $
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