(A) Line emission spectra are used to study the electronic structure: This statement is correct. Line emission spectra are produced when electrons in an atom transition from higher energy levels to lower energy levels, emitting discrete lines of specific wavelengths. These lines correspond to specific energy differences between electron energy levels, providing valuable information about the electronic structure of the atom.
(B) The emission spectra of atoms in the gas phase show a continuous spread of wavelength from red to violet: This statement is incorrect. The emission spectra of atoms in the gas phase do not show a continuous spread of wavelengths from red to violet. Instead, they exhibit distinct and discrete lines at specific wavelengths. These lines correspond to the emission of photons as electrons transition between energy levels. Each line corresponds to a unique energy difference, leading to the emission of light at specific wavelengths.
(C) An absorption spectrum is like the photographic negative of an emission spectrum: This statement is correct. An absorption spectrum is indeed like the photographic negative of an emission spectrum. In an emission spectrum, you observe bright lines at specific wavelengths where electrons are transitioning down energy levels. In an absorption spectrum, you observe dark lines at the same wavelengths where specific frequencies of light are absorbed by the electrons as they move to higher energy levels. This is because the electrons absorb the energy needed to move to higher energy levels, leaving dark lines in the spectrum.
(D) The element helium was discovered in the sun by the spectroscopic method: This statement is correct. The element helium was discovered spectroscopically. During a solar eclipse in 1868, astronomers observed a new yellow line in the solar spectrum, which did not correspond to any known element on Earth. This line was later identified as the spectral signature of helium. Helium was initially discovered in the spectrum of the sun before it was found on Earth. So, out of the given statements, only statement (B) is incorrect, as emission spectra do not show a continuous spread of wavelengths from red to violet.
The correct answer is option (A) : Line emission spectra used to study the electron structure
The emission spectrum of a chemical element or chemical compound is the spectrum of frequencies of electromagnetic radiation emitted due to an electron making a transition from a high energy state to a lower energy state. The photon energy of the emitted photon is equal to the energy difference between the two states.
Read More: Atomic Spectra
The Rydberg formula is the mathematical formula to compute the wavelength of light.
\[\frac{1}{\lambda} = RZ^2(\frac{1}{n_1^2}-\frac{1}{n_2^2})\]Where,
R is the Rydberg constant (1.09737*107 m-1)
Z is the atomic number
n is the upper energy level
n’ is the lower energy level
λ is the wavelength of light
Spectral series of single-electron atoms like hydrogen have Z = 1.