Mg>Al>C>O
Al>B>N>F
Be>Mg>Al>Si
Si>P>Cl>F
The atomic radius decreases across a period from left to right due to the increase in effective nuclear charge, but increases down a group due to the addition of electron shells.
Step 1: \( \text{Be} > \text{Mg} > \text{Al} > \text{Si} \) is incorrect because atomic radius decreases as we move from \( \text{Be} \) to \( \text{Si} \).
Final Conclusion: The incorrect order is Option (3), \( \text{Be} > \text{Mg} > \text{Al} > \text{Si} \)
Match List - I with List - II.
Consider the following statements:
(A) Availability is generally conserved.
(B) Availability can neither be negative nor positive.
(C) Availability is the maximum theoretical work obtainable.
(D) Availability can be destroyed in irreversibility's.
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: