Question:
The function \(x^x; x > 0\) is strictly increasing at
The function \(x^x; x > 0\) is strictly increasing at
Updated On: Apr 26, 2024
- \(\forall x\in R\)
- \(x<\frac{1}{e}\)
- \(x>\frac{1}{e}\)
- \(x<0\)
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The Correct Option is C
Solution and Explanation
The correct answer is Option (C) : \(x>\frac{1}{e}\)
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