Question:

The function $x^x; x > 0$ is strictly increasing at

KCET

Updated On: Apr 26, 2024

$\forall x\in R$
$x<\frac{1}{e}$
$x>\frac{1}{e}$
$x<0$

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The Correct Option is C

Solution and Explanation

The correct answer is Option (C) :

x>\frac{1}{e}

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