Latent heat is the energy absorbed or released during a phase change per unit mass. Hence, it is specific energy:
\[ \text{Latent Heat} = \frac{\text{Energy}}{\text{Mass}}. \]
The dimensional formula of energy is:
\[ \text{Energy} = [ML^2T^{-2}]. \]
Divide by mass:
\[ \text{Latent Heat} = \frac{[ML^2T^{-2}]}{[M]} = [M^0L^2T^{-2}]. \]
Final Answer: \([M^0L^2T^{-2}]\).
The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32