To determine the dimensional formula for latent heat, we need to understand what latent heat refers to. Latent heat is the heat absorbed or released by a substance during a phase change (such as melting or boiling) without a change in temperature. It is usually expressed in energy per unit mass.
The formula for latent heat (L) is:
\(L = \frac{Q}{m}\)where \(Q\) is the total heat absorbed or released, and \(m\) is the mass.
The dimensional formula for heat energy \((Q)\) is: \([M^1 L^2 T^{-2}]\). Mass \((m)\) has the dimensional formula \([M^1]\).
Since \(L = \frac{Q}{m}\), the dimensional formula of latent heat will be calculated as:
\([L] = \frac{[M^1 L^2 T^{-2}]}{[M^1]}\)
After simplifying, we get:
\([L] = [M^0 L^2 T^{-2}]\)
Therefore, the correct dimensional formula for latent heat is: \([M^0 L^2 T^{-2}]\).
Latent heat is the energy absorbed or released during a phase change per unit mass. Hence, it is specific energy:
\[ \text{Latent Heat} = \frac{\text{Energy}}{\text{Mass}}. \]
The dimensional formula of energy is:
\[ \text{Energy} = [ML^2T^{-2}]. \]
Divide by mass:
\[ \text{Latent Heat} = \frac{[ML^2T^{-2}]}{[M]} = [M^0L^2T^{-2}]. \]
Final Answer: \([M^0L^2T^{-2}]\).
Match the LIST-I with LIST-II: 
Choose the correct answer from the options given below:
Match the LIST-I with LIST-II 
Choose the correct answer from the options given below:
A temperature difference can generate e.m.f. in some materials. Let $ S $ be the e.m.f. produced per unit temperature difference between the ends of a wire, $ \sigma $ the electrical conductivity and $ \kappa $ the thermal conductivity of the material of the wire. Taking $ M, L, T, I $ and $ K $ as dimensions of mass, length, time, current and temperature, respectively, the dimensional formula of the quantity $ Z = \frac{S^2 \sigma}{\kappa} $ is:
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
