To determine the dimensional formula for latent heat, we need to understand what latent heat refers to. Latent heat is the heat absorbed or released by a substance during a phase change (such as melting or boiling) without a change in temperature. It is usually expressed in energy per unit mass.
The formula for latent heat (L) is:
\(L = \frac{Q}{m}\)where \(Q\) is the total heat absorbed or released, and \(m\) is the mass.
The dimensional formula for heat energy \((Q)\) is: \([M^1 L^2 T^{-2}]\). Mass \((m)\) has the dimensional formula \([M^1]\).
Since \(L = \frac{Q}{m}\), the dimensional formula of latent heat will be calculated as:
\([L] = \frac{[M^1 L^2 T^{-2}]}{[M^1]}\)
After simplifying, we get:
\([L] = [M^0 L^2 T^{-2}]\)
Therefore, the correct dimensional formula for latent heat is: \([M^0 L^2 T^{-2}]\).
Latent heat is the energy absorbed or released during a phase change per unit mass. Hence, it is specific energy:
\[ \text{Latent Heat} = \frac{\text{Energy}}{\text{Mass}}. \]
The dimensional formula of energy is:
\[ \text{Energy} = [ML^2T^{-2}]. \]
Divide by mass:
\[ \text{Latent Heat} = \frac{[ML^2T^{-2}]}{[M]} = [M^0L^2T^{-2}]. \]
Final Answer: \([M^0L^2T^{-2}]\).
The expression given below shows the variation of velocity \( v \) with time \( t \): \[ v = \frac{At^2 + Bt}{C + t} \] The dimension of \( A \), \( B \), and \( C \) is:
Match List-I with List-II.
Choose the correct answer from the options given below :
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \[ (\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), \] for all \( x, y \in \mathbb{R}. \)
If \( f'(0) = \frac{1}{2} \), then the value of \( 24f''\left( \frac{5\pi}{3} \right) \) is: