Step 1: Determine the dimensional formula for each quantity in List-I.
(A) Mass density:
Mass density (\( \rho \)) is defined as mass per unit volume.
\[
\rho = \frac{\text{Mass}}{\text{Volume}} = \frac{M}{L^3} = ML^{-3}T^{0}
\]
So, (A) matches with (IV).
(B) Impulse:
Impulse (\( J \)) is defined as the change in momentum or the product of force and time.
\[
J = \Delta p = m \Delta v = M \cdot LT^{-1} = MLT^{-1}
\]
Alternatively,
\[
J = F \cdot t = (ma) \cdot t = (MLT^{-2}) \cdot T = MLT^{-1}
\]
So, (B) matches with (II).
(C) Power:
Power (\( P \)) is defined as the rate of doing work or the product of force and velocity.
\[
P = \frac{\text{Work}}{\text{Time}} = \frac{F \cdot d}{t} = \frac{(MLT^{-2}) \cdot L}{T} = ML^2T^{-3}
\]
Alternatively,
\[
P = F \cdot v = (MLT^{-2}) \cdot (LT^{-1}) = ML^2T^{-3}
\]
So, (C) matches with (I).
(D) Moment of inertia:
Moment of inertia (\( I \)) of a particle is given by \( mr^2 \), where \( m \) is mass and \( r \) is the distance from the axis of rotation. For a system of particles or a continuous body, it involves mass and the square of distance.
\[
I = M \cdot L^2 = ML^2T^{0}
\]
So, (D) matches with (III).
Step 2: Match the quantities with their dimensional formulas.
(A) Mass density - \( [ML^{-3}T^{0}] \) - (IV)
(B) Impulse - \( [MLT^{-1}] \) - (II)
(C) Power - \( [ML^2T^{-3}] \) - (I)
(D) Moment of inertia - \( [ML^2T^{0}] \) - (III)
Step 3: Choose the correct option.
The correct matching is (A)-(IV), (B)-(II), (C)-(I), (D)-(III), which corresponds to option (3).