Ma\(_3\)b\(_3\) type complexes show Facial - Meridional isomerism. The isomerism depends on the arrangement of ligands.
\( [Co(NH_3)_3Cl_3] \) forms Ma\(_3\)b\(_3\) isomerism.
\( [Co(NH_3)_4Cl_2]^+ \) forms Ma\(_4\)b\(_2\).
\( [Co(en)_3]^{3+} \) forms M(AA)\(_3\).
\( [Co(en)_2Cl_2]^+ \) forms M(AA)\(_2\)b\(_2\).
Thus, the correct answer is \( [Co(NH_3)_3Cl_3] \), which forms Ma\(_3\)b\(_3\) type complex and shows Facial-Meridional isomerism.
Match List - I with List - II:
List - I:
(A) \([ \text{MnBr}_4]^{2-}\)
(B) \([ \text{FeF}_6]^{3-}\)
(C) \([ \text{Co(C}_2\text{O}_4)_3]^{3-}\)
(D) \([ \text{Ni(CO)}_4]\)
List - II:
(I) d²sp³ diamagnetic
(II) sp²d² paramagnetic
(III) sp³ diamagnetic
(IV) sp³ paramagnetic
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
The compound with molecular formula C\(_6\)H\(_6\), which gives only one monobromo derivative and takes up four moles of hydrogen per mole for complete hydrogenation has ___ \(\pi\) electrons.