The order of absorption of light (wavelength) is determined by the ligand field strength, where stronger field ligands tend to absorb light at shorter wavelengths, while weaker field ligands absorb light at longer wavelengths.
1. A. \([ \text{Co(NH}_3\text{)}_6]^{3+}\): Ammonia (NH₃) is a moderate field ligand.
Thus, this complex absorbs light at a medium wavelength.
2. B. \([ \text{Co(CN)}_6]^{3-}\): Cyanide (CN⁻) is a strong field ligand, leading to a large splitting of d-orbitals and absorption of light at a shorter wavelength (higher energy).
3. C. \([ \text{Cu(H}_2\text{O)}_4]^{2+}\): Water (H₂O) is a weak field ligand, resulting in small d-orbital splitting and absorption at longer wavelengths (lower energy).
4. D. \([ \text{Ti(H}_2\text{O)}_6]^{3+}\): Titanium in the +3 oxidation state (with water ligands) is a relatively weak field complex, leading to light absorption at longer wavelengths compared to ammonia and cyanide complexes.
Thus, the correct order of the wavelength of light absorbed is: \[ C<A<D<B \]
Therefore, the correct answer is (3) C $<$ A $<$ D $<$ B.
Answer the following:
(i) What happens to the colour of the complex \([ \text{Ti(H}_2\text{O)}_6 ]^{3+}\) when heated gradually?
(ii) Write the electronic configuration for a \(d^5\) ion if \(\Delta_o < P\).
(iii) Write the hybridization and magnetic behaviour of the complex \([ \text{Ni(CO)}_4 ]\).
(Atomic number: Ni = 28)
Total number of possible isomers (both structural as well as stereoisomers) of cyclic ethers of molecular formula $C_{4}H_{8}O$ is: