The order of absorption of light (wavelength) is determined by the ligand field strength, where stronger field ligands tend to absorb light at shorter wavelengths, while weaker field ligands absorb light at longer wavelengths.
1. A. \([ \text{Co(NH}_3\text{)}_6]^{3+}\): Ammonia (NH₃) is a moderate field ligand.
Thus, this complex absorbs light at a medium wavelength.
2. B. \([ \text{Co(CN)}_6]^{3-}\): Cyanide (CN⁻) is a strong field ligand, leading to a large splitting of d-orbitals and absorption of light at a shorter wavelength (higher energy).
3. C. \([ \text{Cu(H}_2\text{O)}_4]^{2+}\): Water (H₂O) is a weak field ligand, resulting in small d-orbital splitting and absorption at longer wavelengths (lower energy).
4. D. \([ \text{Ti(H}_2\text{O)}_6]^{3+}\): Titanium in the +3 oxidation state (with water ligands) is a relatively weak field complex, leading to light absorption at longer wavelengths compared to ammonia and cyanide complexes.
Thus, the correct order of the wavelength of light absorbed is: \[ C<A<D<B \]
Therefore, the correct answer is (3) C $<$ A $<$ D $<$ B.
Low spin tetrahedral complexes are not known.
Why is a solution of \(\text{Ni(H}_2\text{O})_6^{2+}\) green while a solution of \(\text{Ni(CN)}_4^{2-}\) is colourless? (At. No. of Ni = 28)
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is :