The order of absorption of light (wavelength) is determined by the ligand field strength, where stronger field ligands tend to absorb light at shorter wavelengths, while weaker field ligands absorb light at longer wavelengths.
1. A. \([ \text{Co(NH}_3\text{)}_6]^{3+}\): Ammonia (NH₃) is a moderate field ligand.
Thus, this complex absorbs light at a medium wavelength.
2. B. \([ \text{Co(CN)}_6]^{3-}\): Cyanide (CN⁻) is a strong field ligand, leading to a large splitting of d-orbitals and absorption of light at a shorter wavelength (higher energy).
3. C. \([ \text{Cu(H}_2\text{O)}_4]^{2+}\): Water (H₂O) is a weak field ligand, resulting in small d-orbital splitting and absorption at longer wavelengths (lower energy).
4. D. \([ \text{Ti(H}_2\text{O)}_6]^{3+}\): Titanium in the +3 oxidation state (with water ligands) is a relatively weak field complex, leading to light absorption at longer wavelengths compared to ammonia and cyanide complexes.
Thus, the correct order of the wavelength of light absorbed is: \[ C<A<D<B \]
Therefore, the correct answer is (3) C $<$ A $<$ D $<$ B.
Given below are two statements:
Statement I: A homoleptic octahedral complex, formed using monodentate ligands, will not show stereoisomerism
Statement II: cis- and trans-platin are heteroleptic complexes of Pd.
In the light of the above statements, choose the correct answer from the options given below
Match the LIST-I with LIST-II
Choose the correct answer from the options given below:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :