Question

The IUPAC name of the coordination compound is: \[ [\text{Rh}(CO)_2I_2]^- \]

• A. dicarbonylidiodidohorodate(I)
• B. dicarbonylidiodidohorodate(I)
• C. carbonylbisiodidorhodium(I)
• D. carbonylidiodiderhodium(I)

Hint:

When naming coordination compounds, the ligands are named alphabetically, and prefixes like "bis" are used when there are multiple identical ligands.

Answer 1

The Correct Option is C

Step 1: Analyze the Coordination Complex.
The coordination compound is \( [\text{Rh}(CO)_2I_2]^-\). It contains: - Two carbonyl (\(CO\)) ligands. - Two iodido (\(I\)) ligands. - The metal ion is rhodium (Rh) in the \(+1\) oxidation state.

Step 2: IUPAC Naming Conventions.
- The name of the metal is "rhodium" and the oxidation state is indicated in Roman numerals as \( \text{Rh}(I) \). - The ligands are named in alphabetical order. The "carbonyl" ligand (CO) is named first, followed by "iodido" (I). - The prefix "bis" is used when there are two identical ligands (in this case, iodido).

Step 3: Conclusion.
Therefore, the IUPAC name is "carbonylbisiodidorhodium(I)", corresponding to option (3).