The energy of the incident photon is: \[ E = \frac{1240}{\lambda} = \frac{1240}{550} \approx 2.25 \, \text{eV} \] For the photoelectric effect to occur, the energy of the photon must be greater than the work function of the metal.
For Cs (work function = 1.9 eV):
Since \( 2.25 \, \text{eV} > 1.9 \, \text{eV} \), photoelectric effect is possible for Cs.
For Li (work function = 2.5 eV):
Since \( 2.25 \, \text{eV} <2.5 \, \text{eV} \), photoelectric effect is not possible for Li.
Thus, the answer is \( \boxed{\text{Cs only}} \).
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: