Question:

The carbohydrates “Ribose” present in DNA is 
A. A pentose sugar 
B. Present in pyranose form 
C. In “D” configuration 
D. A reducing sugar, when free 
E. In \( \alpha \)-anomeric form

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Ribose in DNA exists in the D-configuration and as a pentose sugar. It is a reducing sugar when free and typically forms a furanose ring, not a pyranose ring.
Updated On: Nov 7, 2025
  • A, C and D Only
  • A, B and E Only
  • B, D and E Only
  • A, D and E Only
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The Correct Option is A

Approach Solution - 1

To answer the question regarding the characteristics of the carbohydrate "Ribose" present in DNA, let's examine each option:

  1. A. A pentose sugar
    • Ribose is indeed a pentose sugar. A pentose sugar has five carbon atoms in its molecule. Ribose, in particular, contains an aldehyde group, which classifies it as an aldopentose. In the context of DNA, Deoxyribose, a derived form of ribose with one less oxygen atom, is the sugar present. However, in its basic form, ribose is a pentose sugar. Therefore, this option is correct.
  2. B. Present in pyranose form
    • Ribose generally exists in a furanose form, which is a five-membered ring structure. Pyranose refers to a six-membered ring, which is not typical for ribose. Thus, this statement is incorrect.
  3. C. In "D" configuration
    • Ribose in biological systems usually exists in the D-configuration. The D and L designations refer to the orientation of the asymmetric carbon furthest from the aldehyde or keto group in Fischer projection. Hence, this option is correct.
  4. D. A reducing sugar, when free
    • Ribose, like other aldoses, is a reducing sugar when it is in its free form due to the presence of a free aldehyde group that can be oxidized. Therefore, this option is correct.
  5. E. In \( \alpha \)-anomeric form
    • The anomeric form (\(\alpha\) or \(\beta\)) depends on the specific molecule's configuration in solution. While ribose can exist in both configurations in its cyclic form, specifying "\(\alpha\)-anomer" as a characteristic of ribose in DNA is not accurate. Hence, this option is incorrect.

Based on the above analysis, the correct options are A, C, and D only. The characteristic features of ribose that are consistent with the options provided are as a pentose sugar, with D-configuration, and it being a reducing sugar when in free form.

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Approach Solution -2

Statement A: Ribose is a pentose sugar, which means it contains five carbon atoms. This is true. Ribose is indeed a pentose sugar, so Statement A is true.

Statement B: Ribose in DNA is primarily found in its furanose form, which is a 5-membered ring structure. It is not found primarily in the pyranose form (6-membered ring). Therefore, Statement B is false.

Statement C: Ribose is found in the D-configuration. Ribose is derived from D-galactose, and thus, it exists in the D-configuration. Therefore, Statement C is true.

Statement D: Ribose is a reducing sugar when it is free (i.e., not part of a nucleotide or in its free form). Ribose has a free aldehyde group in its open-chain form, making it a reducing sugar. Therefore, Statement D is true.

Statement E: Ribose can exist in both \( \alpha \)- and \( \beta \)-anomeric forms, depending on the position of the hydroxyl group at the anomeric carbon. However, it is not always in the \( \alpha \)-form. This statement is not always true. Therefore, Statement E is false.

Conclusion:

The correct answer is \( \boxed{(1)} \), which corresponds to Statements A, C, and D being true.

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