The carbohydrates “Ribose” present in DNA is
A. A pentose sugar
B. Present in pyranose form
C. In “D” configuration
D. A reducing sugar, when free
E. In \( \alpha \)-anomeric form
To answer the question regarding the characteristics of the carbohydrate "Ribose" present in DNA, let's examine each option:
Based on the above analysis, the correct options are A, C, and D only. The characteristic features of ribose that are consistent with the options provided are as a pentose sugar, with D-configuration, and it being a reducing sugar when in free form.
Statement A: Ribose is a pentose sugar, which means it contains five carbon atoms. This is true. Ribose is indeed a pentose sugar, so Statement A is true.
Statement B: Ribose in DNA is primarily found in its furanose form, which is a 5-membered ring structure. It is not found primarily in the pyranose form (6-membered ring). Therefore, Statement B is false.
Statement C: Ribose is found in the D-configuration. Ribose is derived from D-galactose, and thus, it exists in the D-configuration. Therefore, Statement C is true.
Statement D: Ribose is a reducing sugar when it is free (i.e., not part of a nucleotide or in its free form). Ribose has a free aldehyde group in its open-chain form, making it a reducing sugar. Therefore, Statement D is true.
Statement E: Ribose can exist in both \( \alpha \)- and \( \beta \)-anomeric forms, depending on the position of the hydroxyl group at the anomeric carbon. However, it is not always in the \( \alpha \)-form. This statement is not always true. Therefore, Statement E is false.
The correct answer is \( \boxed{(1)} \), which corresponds to Statements A, C, and D being true.
Match List - I with List - II:
List - I:
(A) Amylase
(B) Cellulose
(C) Glycogen
(D) Amylopectin
List - II:
(I) β-C1-C4 plant
(II) α-C1-C4 animal
(III) α-C1-C4 α-C1-C6 plant
(IV) α-C1-C4 plant