The angle \( \theta \) made by a vector \( \vec{r} = x\hat{i} + y\hat{j} \) with the x-axis can be calculated using the formula: \[ \tan \theta = \frac{y}{x} \] Where: - \( x = 3 \), - \( y = 3 \). Substituting these values: \[ \tan \theta = \frac{3}{3} = 1 \] Therefore, \[ \theta = \tan^{-1}(1) = 45^\circ \] Thus, the angle made by the vector with the x-axis is \( 45^\circ \).
The correct option is (E) : \(45°\)
The vector is given as $\vec{r} = 3\hat{i} + 3\hat{j}$.
To find the angle $\theta$ made with the x-axis, we use:
$\tan \theta = \frac{\text{y-component}}{\text{x-component}} = \frac{3}{3} = 1$
$\theta = \tan^{-1}(1) = 45^\circ$
Correct answer: 45°
The respective values of \( |\vec{a}| \) and} \( |\vec{b}| \), if given \[ (\vec{a} - \vec{b}) \cdot (\vec{a} + \vec{b}) = 512 \quad \text{and} \quad |\vec{a}| = 3 |\vec{b}|, \] are: