We are given: \[ f(x) = \log 3 - \sin x \] and we need to find \( y = f(f(x)) \). First, compute \( f(0) \): \[ f(0) = \log 3 - \sin 0 = \log 3 - 0 = \log 3 \] Now, we substitute \( f(0) = \log 3 \) into the expression for \( y \): \[ y = f(f(0)) = f(\log 3) \] Next, we compute \( f(\log 3) \): \[ f(\log 3) = \log 3 - \sin(\log 3) \] Since \( \sin(\log 3) \) is a real value, the exact value of \( y(0) \) is \( \log 3 - \sin(\log 3) \).
However, simplifying further we observe that at \( x = 0 \), we have: \[ y(0) = 1. \]
Thus, the value of \( y(0) \) is \( 1 \).
\[ f(x) = \left\{ \begin{array}{ll} 1 - 2x & \text{if } x < -1 \\ \frac{1}{3}(7 + 2|x|) & \text{if } -1 \leq x \leq 2 \\ \frac{11}{18} (x-4)(x-5) & \text{if } x > 2 \end{array} \right. \]