The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
Show Hint
- 13 m
- 30 m
- 11 m
- 10 m
The Correct Option is A
Solution and Explanation
The distance covered by an object is given by the area under the velocity-time graph.
Here, the graph shows a combination of trapezoidal and rectangular areas.
The total area under the graph between \( t = 0 \) and \( t = 4 \) represents the distance traveled.
By calculating the area from the graph: \[ {Distance} = {Area under the graph} = 13 \, {m} \]
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