Question:
$ \lim_{x \to 0} \frac{a^x - 1}{x} $ is equal to
$ \lim_{x \to 0} \frac{a^x - 1}{x} $ is equal to
Updated On: Apr 10, 2025
- \(a\)
- \(\log a\)
- \(0\)
- \(\infty\)
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The Correct Option is B
Solution and Explanation
Using standard limit identity: \[ \lim_{x \to 0} \frac{a^x - 1}{x} = \log_e a = \ln a \]
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