The eccentricity of \((\frac {x}{25})^2 + (\frac {y}{16})^2 = 1\) is:
Note: Assuming the intended equation is \( \frac{x^2}{25} + \frac{y^2}{16} = 1 \) based on the options. The literal interpretation \( \frac{x^2}{625} + \frac{y^2}{256} = 1 \) yields\(e =\frac {\sqrt{369}}{25}\), which is not among the options.