Question:

Let $z_1=2+3 i$ and $z_2=3+4 i$. The set $S=\left\{z \in C:\left|z-z_1\right|^2-\left|z-z_2\right|^2=\left|z_1-z_2\right|^2\right\}$ represents a

Updated On: Mar 20, 2025
  • straight line with the sum of its intercepts on the coordinate axes equals $-18$
  • hyperbola with eccentricity 2
  • hyperbola with the length of the transverse axis 7
  • straight line with the sum of its intercepts on the coordinate axes equals 14
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

1. Expand the given condition: \[ |z - z_1|^2 - |z - z_2|^2 = |z_1 - z_2|^2. \] 2. Substituting \(z = x + yi\), \(z_1 = 2 + 3i\), and \(z_2 = 3 + 4i\), we write: \[ ((x - 2)^2 + (y - 3)^2) - ((x - 3)^2 + (y - 4)^2) = 1^2 + 1^2. \] 3. Simplify the equation: \[ (x^2 - 4x + 4 + y^2 - 6y + 9) - (x^2 - 6x + 9 + y^2 - 8y + 16) = 2. \] 4. After cancellation, we get: \[ 2x + 2y = 14 \implies x + y = 7. \] 5. This represents a straight line with sum of intercepts on the coordinate axes 14. The given condition simplifies to a linear equation \(x + y = 7\), indicating that the locus is a straight line.
Was this answer helpful?
0
0

Concepts Used:

Complex Number

A Complex Number is written in the form

a + ib

where,

  • “a” is a real number
  • “b” is an imaginary number

The Complex Number consists of a symbol “i” which satisfies the condition i^2 = −1. Complex Numbers are mentioned as the extension of one-dimensional number lines. In a complex plane, a Complex Number indicated as a + bi is usually represented in the form of the point (a, b). We have to pay attention that a Complex Number with absolutely no real part, such as – i, -5i, etc, is called purely imaginary. Also, a Complex Number with perfectly no imaginary part is known as a real number.