Question:

Let [x] denote the greatest integer less than or equal to x. If f(x) = [x sinπ x], then f(x) is

Updated On: Aug 8, 2024
  • (A) continuous at x = 0
  • (B) continuous in (-1, 0)
  • (C) differentiable at x = 1
  • (D) differentiable in (-1, 1)
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The Correct Option is A, D

Solution and Explanation

Explanation:
We have, for \(-1[xsinπx]=0Also, xsinπx becomes negative and numerically less than 1 when x is slightly greater than 1 , and so by definition of [x] f(x)=[xsinπx]=1, when \(1Thus, f(x) is constant and equal to 0 in the closed interval [-1,1] and s0f(x) is continuous and differentiable in the open interval (-1,1) At x=1,f(x) is discontinuous. since limi0(1h)=0 and limt0(1+h)=1f(x) is not differentiable at x=1 Hence, options (1),(2) and (4) are correct answers.

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