The formula for the reflection of a point \( Q(x_1, y_1, z_1) \) with respect to a plane \( ax + by + cz + d = 0 \) is given by: \[ x' = x_1 - 2 \cdot \frac{a(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2}, \quad y' = y_1 - 2 \cdot \frac{b(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2}, \quad z' = z_1 - 2 \cdot \frac{c(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2} \] In our case, we need to find the coordinates of \( S \) based on the given reflection formula. To start, we need to express the equation of the plane in standard form.
The equation of the plane is given by: \[ \mathbf{r} = -(t + p)\hat{i} + t\hat{j} + (1 + p)\hat{k} \] The equation of the plane in standard form can be written as: \[ x(t) = -(t + p), \quad y(t) = t, \quad z(t) = 1 + p \] The general form of the plane equation is: \[ Ax + By + Cz + D = 0 \] We now compute the reflection coordinates using this plane equation and the reflection formula.
The position vectors of \( Q \) and \( S \) are provided: \[ \mathbf{Q} = 10\hat{i} + 15\hat{j} + 20\hat{k}, \quad \mathbf{S} = \alpha\hat{i} + \beta\hat{j} + \gamma\hat{k} \] Using the formula for the reflection and substituting the known values, we compute: \[ 3(\alpha + \beta) = -101, \quad 3(\beta + \gamma) = -71, \quad 3(\gamma + \alpha) = -86 \]
Now we compare the results with the given options:
\[ 3(\alpha + \beta) = -101 \] This is correct, as it matches the result from the reflection calculation.
\[ 3(\beta + \gamma) = -71 \] This is also correct.
\[ 3(\gamma + \alpha) = -86 \] This is correct as well.
\[ 3(\alpha + \beta + \gamma) = -121 \] This does not match the reflection calculations, so it is not correct.
The correct options are: A, B, and C.
The vector equations of two lines are given as:
Line 1: \[ \vec{r}_1 = \hat{i} + 2\hat{j} - 4\hat{k} + \lambda(4\hat{i} + 6\hat{j} + 12\hat{k}) \]
Line 2: \[ \vec{r}_2 = 3\hat{i} + 3\hat{j} - 5\hat{k} + \mu(6\hat{i} + 9\hat{j} + 18\hat{k}) \]
Determine whether the lines are parallel, intersecting, skew, or coincident. If they are not coincident, find the shortest distance between them.
Show that the following lines intersect. Also, find their point of intersection:
Line 1: \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} \]
Line 2: \[ \frac{x - 4}{5} = \frac{y - 1}{2} = z \]
Determine the vector equation of the line that passes through the point \( (1, 2, -3) \) and is perpendicular to both of the following lines:
\[ \frac{x - 8}{3} = \frac{y + 16}{7} = \frac{z - 10}{-16} \quad \text{and} \quad \frac{x - 15}{3} = \frac{y - 29}{-8} = \frac{z - 5}{-5} \]
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.
The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____
Mathematically, Geometry is one of the most important topics. The concepts of Geometry are derived w.r.t. the planes. So, Geometry is divided into three major categories based on its dimensions which are one-dimensional geometry, two-dimensional geometry, and three-dimensional geometry.
Consider a line L that is passing through the three-dimensional plane. Now, x,y and z are the axes of the plane and α,β, and γ are the three angles the line makes with these axes. These are commonly known as the direction angles of the plane. So, appropriately, we can say that cosα, cosβ, and cosγ are the direction cosines of the given line L.