The formula for the reflection of a point \( Q(x_1, y_1, z_1) \) with respect to a plane \( ax + by + cz + d = 0 \) is given by: \[ x' = x_1 - 2 \cdot \frac{a(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2}, \quad y' = y_1 - 2 \cdot \frac{b(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2}, \quad z' = z_1 - 2 \cdot \frac{c(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2} \] In our case, we need to find the coordinates of \( S \) based on the given reflection formula. To start, we need to express the equation of the plane in standard form.
The equation of the plane is given by: \[ \mathbf{r} = -(t + p)\hat{i} + t\hat{j} + (1 + p)\hat{k} \] The equation of the plane in standard form can be written as: \[ x(t) = -(t + p), \quad y(t) = t, \quad z(t) = 1 + p \] The general form of the plane equation is: \[ Ax + By + Cz + D = 0 \] We now compute the reflection coordinates using this plane equation and the reflection formula.
The position vectors of \( Q \) and \( S \) are provided: \[ \mathbf{Q} = 10\hat{i} + 15\hat{j} + 20\hat{k}, \quad \mathbf{S} = \alpha\hat{i} + \beta\hat{j} + \gamma\hat{k} \] Using the formula for the reflection and substituting the known values, we compute: \[ 3(\alpha + \beta) = -101, \quad 3(\beta + \gamma) = -71, \quad 3(\gamma + \alpha) = -86 \]
Now we compare the results with the given options:
\[ 3(\alpha + \beta) = -101 \] This is correct, as it matches the result from the reflection calculation.
\[ 3(\beta + \gamma) = -71 \] This is also correct.
\[ 3(\gamma + \alpha) = -86 \] This is correct as well.
\[ 3(\alpha + \beta + \gamma) = -121 \] This does not match the reflection calculations, so it is not correct.
The correct options are: A, B, and C.
Show that the following lines intersect. Also, find their point of intersection:
Line 1: \[ \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} \]
Line 2: \[ \frac{x - 4}{5} = \frac{y - 1}{2} = z \]
As shown in the figures, a uniform rod $ OO' $ of length $ l $ is hinged at the point $ O $ and held in place vertically between two walls using two massless springs of the same spring constant. The springs are connected at the midpoint and at the top-end $ (O') $ of the rod, as shown in Fig. 1, and the rod is made to oscillate by a small angular displacement. The frequency of oscillation of the rod is $ f_1 $. On the other hand, if both the springs are connected at the midpoint of the rod, as shown in Fig. 2, and the rod is made to oscillate by a small angular displacement, then the frequency of oscillation is $ f_2 $. Ignoring gravity and assuming motion only in the plane of the diagram, the value of $\frac{f_1}{f_2}$ is:
The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ____. 
Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80
Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
Mathematically, Geometry is one of the most important topics. The concepts of Geometry are derived w.r.t. the planes. So, Geometry is divided into three major categories based on its dimensions which are one-dimensional geometry, two-dimensional geometry, and three-dimensional geometry.
Consider a line L that is passing through the three-dimensional plane. Now, x,y and z are the axes of the plane and α,β, and γ are the three angles the line makes with these axes. These are commonly known as the direction angles of the plane. So, appropriately, we can say that cosα, cosβ, and cosγ are the direction cosines of the given line L.
