The formula for the reflection of a point \( Q(x_1, y_1, z_1) \) with respect to a plane \( ax + by + cz + d = 0 \) is given by: \[ x' = x_1 - 2 \cdot \frac{a(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2}, \quad y' = y_1 - 2 \cdot \frac{b(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2}, \quad z' = z_1 - 2 \cdot \frac{c(ax_1 + by_1 + cz_1 + d)}{a^2 + b^2 + c^2} \] In our case, we need to find the coordinates of \( S \) based on the given reflection formula. To start, we need to express the equation of the plane in standard form.
The equation of the plane is given by: \[ \mathbf{r} = -(t + p)\hat{i} + t\hat{j} + (1 + p)\hat{k} \] The equation of the plane in standard form can be written as: \[ x(t) = -(t + p), \quad y(t) = t, \quad z(t) = 1 + p \] The general form of the plane equation is: \[ Ax + By + Cz + D = 0 \] We now compute the reflection coordinates using this plane equation and the reflection formula.
The position vectors of \( Q \) and \( S \) are provided: \[ \mathbf{Q} = 10\hat{i} + 15\hat{j} + 20\hat{k}, \quad \mathbf{S} = \alpha\hat{i} + \beta\hat{j} + \gamma\hat{k} \] Using the formula for the reflection and substituting the known values, we compute: \[ 3(\alpha + \beta) = -101, \quad 3(\beta + \gamma) = -71, \quad 3(\gamma + \alpha) = -86 \]
Now we compare the results with the given options:
\[ 3(\alpha + \beta) = -101 \] This is correct, as it matches the result from the reflection calculation.
\[ 3(\beta + \gamma) = -71 \] This is also correct.
\[ 3(\gamma + \alpha) = -86 \] This is correct as well.
\[ 3(\alpha + \beta + \gamma) = -121 \] This does not match the reflection calculations, so it is not correct.
The correct options are: A, B, and C.
List - I | List - II | ||
(P) | γ equals | (1) | \(-\hat{i}-\hat{j}+\hat{k}\) |
(Q) | A possible choice for \(\hat{n}\) is | (2) | \(\sqrt{\frac{3}{2}}\) |
(R) | \(\overrightarrow{OR_1}\) equals | (3) | 1 |
(S) | A possible value of \(\overrightarrow{OR_1}.\hat{n}\) is | (4) | \(\frac{1}{\sqrt6}\hat{i}-\frac{2}{\sqrt6}\hat{j}+\frac{1}{\sqrt6}\hat{k}\) |
(5) | \(\sqrt{\frac{2}{3}}\) |
Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter $ D $ of a tube. The measured value of $ D $ is:
Mathematically, Geometry is one of the most important topics. The concepts of Geometry are derived w.r.t. the planes. So, Geometry is divided into three major categories based on its dimensions which are one-dimensional geometry, two-dimensional geometry, and three-dimensional geometry.
Consider a line L that is passing through the three-dimensional plane. Now, x,y and z are the axes of the plane and α,β, and γ are the three angles the line makes with these axes. These are commonly known as the direction angles of the plane. So, appropriately, we can say that cosα, cosβ, and cosγ are the direction cosines of the given line L.