The correct answer is (D):
aR1b ⇔ ab ≥ 0
So, definitely (a, a) ∈ R1 as a2 ≥ 0
If (a, b) ∈ R1 ⇒ (b, a) ∈ R1
But if (a, b) ∈ R1, (b, c) ∈ R1
⇒ Then (a, c) may or may not belong to R1
{Consider a = –5, b = 0, c = 5 so (a, b) and (b, c) ∈ R1 but ac < 0}
So, R1 is not equivalence relation
a R2 b ⇔ a ≥ b
(a, a) ∈ R2 ⇒ so reflexive relation
If (a, b) ∈ R2 then (b, a) may or may not belong to R2
⇒ So not symmetric
Hence it is not equivalence relation
Match List-I with List-II.
Choose the correct answer from the options given below :
Ordinary Differential Equations is an equation that indicates the relation of having one independent variable x, and one dependent variable y, along with some of its other derivatives.
\(F(\frac{dy}{dt},y,t) = 0\)
A partial differential equation is a type, in which the equation carries many unknown variables with their partial derivatives.
It is the linear polynomial equation in which derivatives of different variables exist. Linear Partial Differential Equation derivatives are partial and function is dependent on the variable.
When the degree of f(x,y) and g(x,y) is the same, it is known to be a homogeneous differential equation.
\(\frac{dy}{dx} = \frac{a_1x + b_1y + c_1}{a_2x + b_2y + c_2}\)
Read More: Differential Equations