Question:

In \( \triangle ABC \) and \( \triangle DEF \), \( \frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF} = \frac{5}{7} \), then the ratio of the areas of \( \triangle ABC \) and \( \triangle DEF \) is:

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The ratio of areas of similar triangles is the square of the ratio of their corresponding sides.
Updated On: Oct 27, 2025
  • 5:7
  • 25:49
  • 49:25
  • 125:343
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The Correct Option is B

Solution and Explanation

For two similar triangles, the ratio of their areas is the square of the ratio of their corresponding sides. Since \( \frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF} = \frac{5}{7} \), the ratio of the areas is: \[ \frac{\text{Area of } \triangle ABC}{\text{Area of } \triangle DEF} = \left( \frac{5}{7} \right)^2 = \frac{25}{49}. \] Thus, the correct answer is \( \boxed{25:49} \).
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