Step 1: Understanding the Concept:
If two angles of one triangle are equal to two angles of another triangle, then the two triangles are similar by the Angle-Angle (AA) similarity criterion. A consequence of this is that their third angles must also be equal.
Step 2: Key Formula or Approach:
The sum of angles in any triangle is 180°.
In \(\triangle DEF\), \(\angle D + \angle E + \angle F = 180^\circ\).
In \(\triangle PQR\), \(\angle P + \angle Q + \angle R = 180^\circ\).
Step 3: Detailed Explanation:
We are given:
\(\angle D = \angle Q\) (Equation 1)
\(\angle E = \angle R\) (Equation 2)
From the sum of angles in \(\triangle DEF\), we can write \(\angle F = 180^\circ - \angle D - \angle E\).
From the sum of angles in \(\triangle PQR\), we can write \(\angle P = 180^\circ - \angle Q - \angle R\).
Now substitute the given equalities (Equations 1 and 2) into the equation for \(\angle P\):
\[ \angle P = 180^\circ - (\angle D) - (\angle E) \]
Comparing this with the equation for \(\angle F\), we see that:
\[ \angle F = \angle P \]
Step 4: Final Answer:
The correct statement is \(\angle F = \angle P\).
In the adjoining figure, \( \triangle CAB \) is a right triangle, right angled at A and \( AD \perp BC \). Prove that \( \triangle ADB \sim \triangle CDA \). Further, if \( BC = 10 \text{ cm} \) and \( CD = 2 \text{ cm} \), find the length of } \( AD \).
If a line drawn parallel to one side of a triangle intersecting the other two sides in distinct points divides the two sides in the same ratio, then it is parallel to the third side. State and prove the converse of the above statement.
In the adjoining figure, \( AP = 1 \, \text{cm}, \ BP = 2 \, \text{cm}, \ AQ = 1.5 \, \text{cm}, \ AC = 4.5 \, \text{cm} \) Prove that \( \triangle APQ \sim \triangle ABC \).
Hence, find the length of \( PQ \), if \( BC = 3.6 \, \text{cm} \).