In the given compound, the number of 2° carbon atom/s is _____.
- Three
- One
- Two
- Four
The Correct Option is B
Solution and Explanation
The compound has a branched structure with the central carbon atom being tertiary (\(3\degree\)). The carbons attached to it are primary (\(1\degree\)) and secondary (\(2\degree\)). Only one carbon atom in this molecule is secondary (attached to two other carbons).
Top Questions on functional groups
- Which of the following functional groups is NOT present in Aspartame?
- BCECE - 2025
- Chemistry
- functional groups
- A medicine compound having an amide linkage was asked. Which of the following compounds contains an amide linkage?
- MHT CET - 2025
- Chemistry
- functional groups
- Identify one functional group in the given organic compound O₃.
- Bihar Board XII - 2023
- Chemistry
- functional groups
- The functional group of a secondary amine is
- Bihar Board XII - 2023
- Chemistry
- functional groups
- Identify A, B and C in the sequence :
- KCET - 2023
- Chemistry
- functional groups
Questions Asked in JEE Main exam
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
- JEE Main - 2025
- Relations and functions
- Density of 3 M NaCl solution is 1.25 g/mL. The molality of the solution is:
- JEE Main - 2025
- Solutions
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.- JEE Main - 2025
- Electrical Circuits
- Let \( \vec{a} = \hat{i} + 2\hat{j} + \hat{k} \) and \( \vec{b} = 2\hat{i} + 7\hat{j} + 3\hat{k} \). Let \( L_1 : \vec{r} = (-\hat{i} + 2\hat{j} + \hat{k}) + \lambda \vec{a}, \lambda \in {R} \) and \( L_2 : \vec{r} = (\hat{j} + \hat{k}) + \mu \vec{b}, \mu \in \mathbb{R} \) be two lines. If the line \( L_3 \) passes through the point of intersection of \( L_1 \) and \( L_2 \), and is parallel to \( \vec{a} + \vec{b} \), then \( L_3 \) passes through the point:
- JEE Main - 2025
- Vectors
For $ \alpha, \beta, \gamma \in \mathbb{R} $, if $$ \lim_{x \to 0} \frac{x^2 \sin \alpha x + (\gamma - 1)e^{x^2} - 3}{\sin 2x - \beta x} = 3, $$ then $ \beta + \gamma - \alpha $ is equal to: