The carbylamine reaction, also known as the isocyanide test, is a chemical test used for the detection of primary amines. In this reaction, a primary amine reacts with chloroform in the presence of a base (typically potassium hydroxide) to form an isocyanide.
The resulting foul-smelling product formed in the carbylamine test is an:
Isocyanide (also known as a carbylamine)
Therefore, among the options provided, the correct representation of the product would be:
\(CH_3NC\)
It is important to note that isocyanides are highly toxic compounds with an intensely unpleasant odor, which is why the carbylamine test is easily recognizable. Thus, the foul smelling product is: Option 1
The Carbylamine test is used to identify primary amines. When a primary amine reacts with chloroform (\(\text{CHCl}_3\)) and alcoholic potassium hydroxide (\(\text{KOH}\)), it produces an isocyanide (also called isonitrile), which has a foul smell.
For methylamine (\(\text{CH}_3\text{NH}_2\)), the product is:
\[ \text{CH}_3\text{NH}_2 + \text{CHCl}_3 + 3\text{KOH} \rightarrow \text{CH}_3\text{NC} + 3\text{KCl} + 3\text{H}_2\text{O} \]
Hence, the foul-smelling product is: \(\text{CH}_3\text{NC}\)
Correct answer: (A) \(\text{CH}_3\text{NC}\)
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):
A wooden block of mass M lies on a rough floor. Another wooden block of the same mass is hanging from the point O through strings as shown in the figure. To achieve equilibrium, the coefficient of static friction between the block on the floor and the floor itself is
The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: