To identify A, B, and C, let's break down the reaction steps:
Starting compound: The initial compound is CH₃CH₂Br (ethyl bromide), which is undergoing the following reactions.
Step 1: Reaction with KCN (alc):
The reaction with KCN in alcohol will cause a nucleophilic substitution reaction, where the bromine is replaced by a cyanide (CN) group. This gives the product CH₃CH₂CN (ethyl cyanide or propionitrile).
Therefore, A = CH₃CH₂CN.
Step 2: Reaction with LiAlH₄:
The reaction of nitriles with LiAlH₄ (Lithium aluminium hydride) reduces the nitrile group (CN) to an amine group (NH₂).
Therefore, B = CH₃CH₂CH₂NH₂ (ethylamine).
Step 3: Reaction with HNO₂ (Nitrous acid) at 0°C:
The reaction of amines with nitrous acid (HNO₂) at low temperatures leads to diazotization of the amine group and its subsequent replacement by a hydroxyl group. This converts the amine to an alcohol.
Therefore, C = CH₃CH₂CH₂OH (ethanol).
A = CH₃CH₂CN (ethyl cyanide)
B = CH₃CH₂CH₂NH₂ (ethylamine)
C = CH₃CH₂CH₂OH (ethanol)
Option 1: CH₃CH₂CN, CH₃CH₂CH₂NH₂, CH₃CH₂CH₂OH is the correct answer.