Question:

In the following substitution reaction:

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In substitution reactions, the leaving group is displaced by a nucleophile, leading to a new product. The order and nature of the nucleophile and leaving group affect the reaction outcome.
Updated On: May 1, 2025
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The Correct Option is A

Solution and Explanation

Explanation of the Substitution Reaction:

The given problem involves a substitution reaction, where an atom or group in a molecule is replaced by another atom or group. To solve the problem, we need to identify the reaction mechanism and the reagents involved to determine the correct product.

In substitution reactions, particularly in organic chemistry, two common types are:

  • SN1 Reactions: Unimolecular nucleophilic substitution, where a carbocation intermediate forms. These reactions are typically seen with tertiary substrates.
  • SN2 Reactions: Bimolecular nucleophilic substitution, where a direct displacement occurs without intermediates. These reactions occur with primary and secondary substrates.

A benzene ring with two bromine atoms and a nitro group ($NO_2$). Sodium ethoxide ($C_2H_5ONa$) in ethanol ($C_2H_5OH$) is a strong nucleophile and a base. The nitro group is an electron-withdrawing group, which activates the benzene ring towards nucleophilic aromatic substitution, particularly at the positions ortho and para to it.

In this case, one of the bromine atoms will be replaced by the ethoxide group ($OC_2H_5$). The bromine atom that is more activated by the nitro group will be substituted preferentially. Since both bromine atoms are ortho to the nitro group, they are equally activated. Therefore, the product will be the substitution of one of the bromine atoms with the ethoxide group.

<p>The product 'P' formed is: </p>

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