Propene to 1-Iodopropane
To convert propene to 1-iodopropane, hydroiodic acid (HI) is used in an electrophilic addition reaction.
The double bond in propene reacts with HI. According to Markovnikov's rule, the hydrogen atom from HI attaches to the carbon with more hydrogen atoms, and the iodine attaches to the other carbon, forming the desired product.
\( \text{CH}_2=\text{CHCH}_3 + \text{HI} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{I} \)
Product: 1-iodopropane
Draw the structure of the major monohalo product for each of the following reactions:
Br\(_2\)/CS\(_2\)
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)
In the following substitution reaction:
An object has moved through a distance can it have zero displacement if yes support your answer with an example.
Acidified \(KMnO_4\) oxidizes sulphite to:
The correct IUPAC name of \([ \text{Pt}(\text{NH}_3)_2\text{Cl}_2 ]^{2+} \) is:
Consider the following compounds:
(i) CH₃CH₂Br
(ii) CH₃CH₂CH₂Br
(iii) CH₃CH₂CH₂CH₂Br
Arrange the compounds in the increasing order of their boiling points.
Alkyl halides undergoing nucleophilic bimolecular substitution reaction involve: