Propene to 1-Iodopropane
To convert propene to 1-iodopropane, hydroiodic acid (HI) is used in an electrophilic addition reaction.
The double bond in propene reacts with HI. According to Markovnikov's rule, the hydrogen atom from HI attaches to the carbon with more hydrogen atoms, and the iodine attaches to the other carbon, forming the desired product.
\( \text{CH}_2=\text{CHCH}_3 + \text{HI} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{I} \)
Product: 1-iodopropane
Draw the structure of the major monohalo product for each of the following reactions:
Br\(_2\)/CS\(_2\)
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)
In the following substitution reaction: