Concept: This problem uses the Basic Proportionality Theorem (BPT), also known as Thales' Theorem, and its corollaries. If a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio.
A corollary is that if DE \(||\) BC in \(\triangle \text{ABC}\), then \(\frac{\text{AD}}{\text{AB}} = \frac{\text{AE}}{\text{AC}}\).
Step 1: Understand the given ratio and relate it to sides of \(\triangle \text{ABC}\)
Given: DE \(||\) BC in \(\triangle \text{ABC}\).
Given ratio: \(\frac{\text{AD}}{\text{DB}} = \frac{3}{5}\).
This means we can let AD = \(3k\) and DB = \(5k\) for some constant \(k\).
Then, the full side AB = AD + DB = \(3k + 5k = 8k\).
So, the ratio \(\frac{\text{AD}}{\text{AB}} = \frac{3k}{8k} = \frac{3}{8}\).
Step 2: Apply the corollary of the Basic Proportionality Theorem
Since DE \(||\) BC, by the corollary of BPT:
\[ \frac{\text{AD}}{\text{AB}} = \frac{\text{AE}}{\text{AC}} \]
Step 3: Substitute the known values into the proportion
We found \(\frac{\text{AD}}{\text{AB}} = \frac{3}{8}\).
Given AC = 4.8 cm.
Let AE = \(x\) cm (this is what we need to find).
Substituting these into the proportion:
\[ \frac{3}{8} = \frac{\text{AE}}{4.8} \]
\[ \frac{3}{8} = \frac{x}{4.8} \]
Step 4: Solve for AE (\(x\))
To solve for \(x\), multiply both sides by 4.8:
\[ x = \frac{3}{8} \times 4.8 \]
\[ x = \frac{3 \times 4.8}{8} \]
We can simplify \(4.8/8\). Note that \(48/8 = 6\), so \(4.8/8 = 0.6\).
\[ x = 3 \times 0.6 \]
\[ x = 1.8 \]
So, AE = 1.8 cm.
This matches option (1).