If \(\frac{5+9+13+…… \text{ to } n \text{ terms}}{7+9+11+……. \text{ to } (n+1) \text{ terms}}\) \(= \frac{17}{16}\) then\(n =\)
In the given figure \(\triangle \text{ABC}\) is an equilateral triangle of side 8 cm. A,B and C are the centres of circular arcs of radius 4 cm. Find the area of the shaded region correct upto 2 decimal places (\(\pi = 3.142, \sqrt{3} = 1.732\)): Equilateral triangle ABC. From each vertex (A, B, C), a circular sector is drawn inside the triangle. Radius of each sector is 4 cm. Side of triangle is 8 cm. The shaded region is the area of the triangle MINUS the areas of these three sectors.
In the given figure \( \angle CAB = 90^\circ \) and AD \(\perp\) BC. If AC = 25 cm, AB = 1m and BD = 96.08 cm, then find the value of AD Visual shows triangle CAB with right angle at A. AD is perpendicular to BC, with D on BC. Labels: AC=25cm, AB=1m. BD=96.08cm is marked on the hypotenuse segment.