In △ABC, if a : b : c = 4 : 5 : 6, then the ratio of the circumference to its in radius is
16:7
25:11
5:4
9:5
The correct option is: 16:7.
Assuming: a=4k, b=5k, c=6k,
The semi-perimeter, s, is given as: s=2a+b+c=215k.
Hence, the area ΔΔ can be calculated using Heron's formula: Δ=s(s−a)(s−b)(s−c)=15k2⋅7k2⋅5k2⋅3k2=157k2.
As a result, the inradius (r) is determined by: r=sΔ=15k2157k2=7k.
The circumradius (R) can be obtained using the formula: R=4Δabc=4⋅157k24k⋅5k⋅6k=607k120k3=27k.
Thus, the ratio R:r can be expressed as: rR=7k27k=727=2.
Hence, the required ratio is 16:7
List - I | List - II | ||
(P) | γ equals | (1) | \(-\hat{i}-\hat{j}+\hat{k}\) |
(Q) | A possible choice for \(\hat{n}\) is | (2) | \(\sqrt{\frac{3}{2}}\) |
(R) | \(\overrightarrow{OR_1}\) equals | (3) | 1 |
(S) | A possible value of \(\overrightarrow{OR_1}.\hat{n}\) is | (4) | \(\frac{1}{\sqrt6}\hat{i}-\frac{2}{\sqrt6}\hat{j}+\frac{1}{\sqrt6}\hat{k}\) |
(5) | \(\sqrt{\frac{2}{3}}\) |
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