Question:

In a triangle PQR, $\angle PRQ = 90^\circ$. What is $PR + RQ$?
Statement A
A. The diameter of the incircle is $10$.

Statement B
B. The diameter of the circumcircle is $18$.

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In right triangles, inradius and circumradius formulas combined can yield sums of legs if hypotenuse is known.
Updated On: Aug 5, 2025
  • The question can be answered by one of the statements alone but not by the other.
  • The question can be answered by using either statement alone.
  • The question can be answered by using both the statements together, but cannot be answered by using either statement alone.
  • The question cannot be answered even by using both statements together.
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The Correct Option is C

Solution and Explanation

From Statement A: Inradius $r = 5$, but without another dimension, $PR+RQ$ cannot be determined.
From Statement B: Circumradius $R = 9$ in a right triangle means hypotenuse $PQ = 18$, but $PR+RQ$ still cannot be found directly.
Combining both: In a right triangle, $r = \frac{PR + RQ - PQ}{2}$. Knowing $r = 5$ and $PQ = 18$, we solve for $PR + RQ = 28$. Thus, both statements together are needed.
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