Question:

If the length of a side of a rhombus is 36 cm and the area of the rhombus is 396 sq. cm, then the absolute value of the difference between the lengths, in cm, of the diagonals of the rhombus is:

Show Hint

For any rhombus with side length \(a\) and diagonals \(d_1, d_2\), use: \[ d_1^2 + d_2^2 = 4a^2, \qquad \text{and} \qquad \text{Area} = \frac12 d_1 d_2. \] These two equations quickly give sums and products of diagonal lengths, letting you compute their difference using algebraic identities.
Updated On: Dec 5, 2025
Hide Solution
collegedunia
Verified By Collegedunia

Correct Answer: 60

Solution and Explanation

Let the diagonals of the rhombus be \(d_1\) and \(d_2\). Side length of the rhombus is \(a = 36\) cm. Step 1: Use the area formula. \[ \text{Area} = \frac{1}{2} d_1 d_2 = 396 \] \[ d_1 d_2 = 792. \]
Step 2: Use the diagonal–side relationship. Diagonals of a rhombus bisect each other at right angles, so by Pythagoras: \[ \left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2 = a^2. \] Multiply by 4: \[ d_1^2 + d_2^2 = 4a^2 = 4(36^2) = 5184. \]
Step 3: Compute \(|d_1 - d_2|\). Use the identity: \[ (d_1 - d_2)^2 = d_1^2 + d_2^2 - 2 d_1 d_2. \] Substitute known values: \[ (d_1 - d_2)^2 = 5184 - 2(792) = 5184 - 1584 = 3600. \] \[ |d_1 - d_2| = \sqrt{3600} = 60. \] Thus, the required difference between the diagonals is: \[ \boxed{60}. \]
Was this answer helpful?
0
0

Top Questions on Geometry

View More Questions

Questions Asked in CAT exam

View More Questions