Question:

If the straight line y = mx lies outside of the circle x²+ y²– 20y + 90 = 0, then the value of m will satisfy

WBJEE

Updated On: Apr 23, 2024

(A) m < 3
(B) |m| < 3
(C) m > 3
(D) |m| > 3

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The Correct Option is B

Solution and Explanation

Explanation:

\begin{array}{l} x^{2} + m^{2} x^{2} - 20 m x + 90 \\ x^{2} (1 + m^{2}) - 20 m x + 90 = 0 \\ D < 0 \\ 400 m^{2} - 4 \times 90 (1 + m^{2}) < 0 \\ 40 m^{2} < 360 \\ m^{2} < 9; ∣ m k 3 \end{array}

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