Question

If the straight line  y = mx lies outside of the circle x²+ y²– 20y + 90 = 0, then the value of m will satisfy 

• (A) m < 3
• (B) |m| < 3
• (C) m  > 3
• (D) |m| > 3

Answer 1

The Correct Option is B

Explanation:
$$\begin{array}{l}{x}^2+m^2{x}^2-20mx+90\\ x^2(1+m^2)-20mx+90=0\\ D<0\\ 400m^2-4\times 90(1+m^2)<0\\ 40m^2<360\\ m^2<9;\mid mk3\end{array}$$