If the CFSE of $\left[ Ti \left( H _2 O \right)_6\right]^{3+}$ is $-960 kJ / mol$, this complex will absorb maximum at wavelength ___$nm$ (nearest integer) Assume Planck's constant $( h )=64 \times 10^{-34} Js$, Speed of light $( c )=30 \times 10^8 m / s$ and Avogadro's Constant $\left( N _{ A }\right)=6 \times 10^{23} / mol$
Correct Answer: 480
Solution and Explanation
(Ti+3(H2O)6)3+
Ti+3:3d1
C.F.S.E. =−0.4×Δ0
\(=−\frac{96×103}{N_0}J \)
\(Δ_0=\frac{96×10^3 }{0.4×6×10^{23}}\)
\(⇒\frac{hc}{λ}=\frac{96×10^3 }{0.4×6×10^{23}}\)
\(λ=\frac{0.4×6×10^{23}×6.4×10^{−34}×3×10^8 }{96×10^3}\)
\(=0.48×10^{−6}m \)
\(=480×10^{−9}m \)
=480nm
So , the correct answer is 480.
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.