Step 1: Manganese (II) salts, such as \( {Mn}^{2+} \), can be oxidized to the permanganate ion \( {MnO}_4^- \) by various oxidizing agents.
Step 2: Among the Option:
- Hydrogen peroxide is commonly used to oxidize manganese (II) to permanganate, but it is not the best oxidizer in this case.
- Conc. nitric acid does not efficiently oxidize manganese (II) to permanganate.
- Peroxy disulphate (\( {(O}_2{SO}_2{)}_2^{2-} \)) is a powerful oxidizing agent and is known to oxidize \( {Mn}^{2+} \) to \( {MnO}_4^- \), making it the correct choice in this context.
- Dichromate is also an oxidizing agent but does not directly oxidize manganese (II) to permanganate.
Thus, the correct answer is option (C).
If the CFSE of $\left[ Ti \left( H _2 O \right)_6\right]^{3+}$ is $-960 kJ / mol$, this complex will absorb maximum at wavelength ___$nm$ (nearest integer) Assume Planck's constant $( h )=64 \times 10^{-34} Js$, Speed of light $( c )=30 \times 10^8 m / s$ and Avogadro's Constant $\left( N _{ A }\right)=6 \times 10^{23} / mol$
Evaluate the following limit: $ \lim_{n \to \infty} \prod_{r=3}^n \frac{r^3 - 8}{r^3 + 8} $.
In the given cycle ABCDA, the heat required for an ideal monoatomic gas will be:
A particle is moving in a straight line. The variation of position $ x $ as a function of time $ t $ is given as:
$ x = t^3 - 6t^2 + 20t + 15 $.
The velocity of the body when its acceleration becomes zero is: